Question

the sum and product of three numbers in AP are 24 and 48 respectively find the numbers​

Answer 1

Answer:

Step-by-step explanation:

Let the numbers be a-d,a,a+d

A.T.Q

a-d+a+a+d=24

3a=24

a=8

(a-d)a(a+d)=48

(a-d)(a+d)=48/a

Putting (a-d)(a+d)=a^2-d^2

a^2-d^2=6

64-d^2=6

-d^2=-58

d=7.62(as root 58=7.62)

Numbers=a+d=15.62

a=8

a-d=0.38

Answer 2

Heya Mate ur answer is...

Let the nos. be a+r,a,a-r

Now, a+r+a+a-r=24

3a=24

a=8

Now, By the question,

(8+r)(8-r)8=480

(64-r²)8=480

512-8r²=480

32=8r²

r²=4

r=2/-2

So, nos are -- 10,8,6

6,8,10

Hope it helps ❤❤❤❤