the sum of 1st 10 terms of a.p is 25 and the common difference is twice the 1st term .find the 10th term?
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Sum of first ten terms =25
That is (10(2a+9(2a))/2=25
10(20a)=50
20a=5
a=5/20
a=1/4
Then t10=a+9d=a+9(2a)
=19a=19/4
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