The sum of 1st 7 term of a ap is 77.find the 4th term
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SOLUTION....
Sn = n/2 [2a+(n-1)d]
where,
n= 7 ,Sn = 77, a = first term and d = common difference.
S7 = 7/2 [ 2a + (7-1)d]
77 = 3.5 [2a + 6d]
77/3.5 = 2a + 6d
22 = 2a + 6d
☞ a + 3d = 11.
☞ a4 = 11.
Hence the fourth term is 11.
Hope this will help you.....☺☺
☛ ⛧⛧ Mr. Thakur ⛧⛧
Sn = n/2 [2a+(n-1)d]
where,
n= 7 ,Sn = 77, a = first term and d = common difference.
S7 = 7/2 [ 2a + (7-1)d]
77 = 3.5 [2a + 6d]
77/3.5 = 2a + 6d
22 = 2a + 6d
☞ a + 3d = 11.
☞ a4 = 11.
Hence the fourth term is 11.
Hope this will help you.....☺☺
☛ ⛧⛧ Mr. Thakur ⛧⛧
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Hi... Here's the solution
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