Question

The sum of 2 digit no.is 8.the no obtained by reversing the digits exceeds the original number by 36. Find tthe number ?

Answer 1

Let the unit digit be x

Tens digit=8-x

Value of no=10(8-x)+x

=80-10x+x

=80-9x

On reversing

unit digit=8-x

Tens digit=x

Value of no=10x+8-x

=9x+8

ACC to ques

9x+8-(80-9x)=36

9x+8-80+9x=36

18x-72=36

18x=36+72

18x=108

x=108/18=6

unit digit=6

Tens digit=8-x=8-6=2

No=26