Question

the sum of 2 digit number and the number of obtained by interching the digit in unit place is greater than the digit in the tensplace by 5 find the number

Answer 1

Let the unit digit be X and ten 's digit be Y. So, original digit be ( X+10.Y) , And by reversing the digit we get (Y+10.x)SO ACCORDINGTO THE QUESTION(X+10Y)+(Y+10X) = 6611X+11Y = 6611(X+Y) = 66X+Y = 66/11X+Y = 6 ------------------- 1And, since digits differ by 2So, X-Y = 2 --------------- 2Adding 1 and 2 equations we get2X = 8X = 8/2so, X = 4And, puttingvalue of Xin equation 1X + Y = 64 + Y = 6Y = 6 - 4Y = 2Therefore, number is given by putting value of X & YHence, number is ( 4+10*2) = 24...