the sum of 2 number is 9 its reciprocal is 1/2 find the number
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Let the first number be a
Second number = 9 - a
According to question,
1/a + 1/ ( 9 - a) = 1/2
=> ( 9-a + a) / a(9 - a) = 1/2
=> 9 / 9a - a^2 = 1/2
=> 18 = 9a - a^2
=> a^2 - 9a + 18 = 0
=> a^2 - 6a - 3a + 18 = 0
=> a ( a - 6) - 3(a-6) = 0
=> (a-6)(a-3) = 0
First number = 6
Second number = 3
Or
First number = 3
Second number = 6
Second number = 9 - a
According to question,
1/a + 1/ ( 9 - a) = 1/2
=> ( 9-a + a) / a(9 - a) = 1/2
=> 9 / 9a - a^2 = 1/2
=> 18 = 9a - a^2
=> a^2 - 9a + 18 = 0
=> a^2 - 6a - 3a + 18 = 0
=> a ( a - 6) - 3(a-6) = 0
=> (a-6)(a-3) = 0
First number = 6
Second number = 3
Or
First number = 3
Second number = 6
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