the sum of 2 numbers is 50. if the larger number is divided by the smaller number we get quotient as 2 and remainder as 3.Find the numbers
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Answered by
1
x + y = 50 or x = 50-y
x/y = 2 + 3/y now substitute x = 50-y
(50-y)/y = 2 + 3/y multiply equation by y
50-y = 2y + 3
47= 3y
Y = 47/3
X = 50 - y
= 50 - 47/3
= 103/3
x/y = 2 + 3/y now substitute x = 50-y
(50-y)/y = 2 + 3/y multiply equation by y
50-y = 2y + 3
47= 3y
Y = 47/3
X = 50 - y
= 50 - 47/3
= 103/3
aruchigu:
but if u verify it u get the remainder as 9 not 3
Answered by
0
let the two numbers be x and y ;
x+y = 50
x = 50-y
x = 2y +3
50-y = 2y+3
47 = 3y
y = 15.66
x = 50-15.66
x = 34.34
hence the required numbers are 15.66 and 34.34
x+y = 50
x = 50-y
x = 2y +3
50-y = 2y+3
47 = 3y
y = 15.66
x = 50-15.66
x = 34.34
hence the required numbers are 15.66 and 34.34
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