Question

The sum of 2 numbers is 80 and the greater number exceeds twice the small number by 11. Find the numbers.

Answer 1

 Let us assume, x and y are the two numbers and x > y

Given:

x + y = 80 -----------1

Also given:

x = 2y + 11 --------------2

Substitute the value of x from equation 1 in equation 2

2y + 11 + y = 80

3y + 11 = 80

3y = 69

y = 23

Therefore, x = 2y + 11 = (2 * 23) + 11 = 57

The two numbers are 57 and 23 

hope it helps you

Answer 2

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Hey friend,

Here is your answer.....

Let the smaller number be x.

So, bigger number = 11 + 2x

Sum of the numbers = 80

So, 2x + 11 + x = 80

3x + 11 = 80

3x = 80 - 11

3x = 69

x = 69 /3 = 23

So the numbers are 23 and 57.

Hope it will help !

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