the sum of 2nd and 7th is 30 , if the 13th term is one less than twice it's 8th term , find A.P.
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let the AP be a,a+d,a+2d............a+(n-1)d
T2= a+d T7=a+6d
a+d+a+6d=30 , 2a+7d=30.............(1)
T13=a+12d , T8=a+7d
T13=2(T8)-1
a+12d=2a+14d-1
a+2d=1..................(2)
a=1-2d subsitute the value of a in eq(1)
2(1-2d)+7d=30
2-4d+7d=30
d=4
a= 1-2(4)
a=-7
AP= -7,-3,1............
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