Question

the sum of 3/8 + 3 / 8 +.....40 times is what ?​

Answer 1

Here,

a=3/8

d=3/8-3/8

=0

so sum upto 40times,S40

=n/2{2a+(n-1)d}

=20/2{2×3/8+(20-1)×0}

=10×3/4

=30/4

YOU CAN USE CALCULATOR AND VERIFY MY RESULT.❣

Answer 2

The sum of $\dfrac{3}{8}+\dfrac{3}{8}+......$ (40 times )  is 15.

Explanation:

We know that in Mathematics the sum of a repeating series a+a+a+a....a (n times) is n x a.  (Also known as Multiplication rule.)

For example , the sum of 2+2+2+2+....(20 times) is 20 x 2=40

Similarly , the sum of $\dfrac{3}{8}+\dfrac{3}{8}+......$   (40 times ) will be:

$40\times\dfrac{3}{8}=5\times3=15$

Hence, the sum of $\dfrac{3}{8}+\dfrac{3}{8}+......$ (40 times )  is 15.

# Learn more:

Find the sum of find the sum of minus 3 and 6 ​

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