The sum of 3 consecutive even numbers is 126. What are the numbers ?
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1st number = x
2nd number = x+2
3rd number = x+4
now , we will set a equation
x + x+2 + x + 4 = 126
3x + 6 = 126
3x = 126 - 6
3x = 120
x = 120/3
x = 40
1st number = 40
2nd number = 40 + 2 = 42
3rd number = 40 + 4 = 44
2nd number = x+2
3rd number = x+4
now , we will set a equation
x + x+2 + x + 4 = 126
3x + 6 = 126
3x = 126 - 6
3x = 120
x = 120/3
x = 40
1st number = 40
2nd number = 40 + 2 = 42
3rd number = 40 + 4 = 44
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