Question

The sum of 3 consecutive even numbers is 44 more than the average of these numbers.What will be the highest of these numbers

Answer 1

let the three consecutive even no be n, n+2,n+4
according to question
n+n+2+n+4=44+(n+n+2+n+4)3
3n+6=44+n+2
2n=40
n=20
hence the highest no be n+4=24 ok

Answer 2

Dear Student,

◆ Answer -

Highest no = 24

● Explaination -

Let x be smallest no. Then other two consecutive no are x, x+2 and x+4.

From given condition,

(x + x+2 + x+4) = (x + x+2 + x+4)/3 + 44

(x + x+2 + x+4) - (x + x+2 + x+4)/3 = 44

2/3 (x + x+2 + x+4) = 44

3x + 6 = 44×3/2

3x = 66 - 6

x = 60 / 3

x = 20

So the highest no is -

x + 4 = 20 + 4

x + 4 = 24

Hence, the highest of given numbers is 24.

Thanks dear. Hope this helps you...