Question

the sum of 3 consecutive integers is -24 what are the three integers

Answer 1

Given:

The sum of three consecutive integers is (-24)

To be found:

All the three integers whose sum is equal to (-24)

Now,

Let the three consecutive integers be

(n), (n+1), and (n+2)

Now,

According to the question,

Their sum is equal to (-24)

So,

⇒ (n) + (n+1) + (n+2) = -24

⇒ n + n + n + 1 + 2 = -24

⇒ 3n + 3 = -24

⇒ 3n = -24 - 3

[∵ Taking 3 to RHS]

⇒ 3n = -27

⇒ n = -27 ÷ 3

⇒ n = -9

So,

The first integer is n = (-9)

Second integer is (n+1) = (-9 + 1) = (-8)

And the third integer is (n+2) = (-9 +2) = -7

Hence,

The three consecutive integers are (-9), (-8), (-7)

- - -

Verification:

Sum

= (-9) + (-8) + (-7)

= -24

Hence, verified.

Answer 2

$\bf { \underline{ \underline{ \red{Answer : - }}}}$

Given:-

• The sum of 3 consecutive integers is -24

Solution:-

Let the three consecutive integers are x, x+1, x+2

According to Question,

x+x+1+x+2=-24

3x+3=-24

3x=-24-3

3x=-27

x=-27/3

x=-9

now,

• x =-9
• x+1=-9+1=-8
• x+2=-9+2=-7

therefore,

The three consecutive integers are -9 , -8 and -7.

Verification:-

-9+(-8)+(-7)=-9-8-7=-24.