Question

The sum of 3 consecutive integers is 30.
The sum of their square is

Answer 1

let the three consecutive integers be a - 1, a, a + 1

a - 1 + a + a + 1 = 30

3a = 30

a = 10

hence, the numbers are

a - 1 = 10 - 1 = 9

a = 10

a + 1 = 10 + 1 = 11

=> 9² + 10² + 11²

= 81 + 100 + 121

= 302

Hence, sum of squares of given three consecutive integers is 302.

Answer 2

Answer:302

Step-by-step explanation:

Let the three consecutive nos be

x + x+1 + x+2 = 30

3x +3 = 30

3x = 27

x =9

..9²+10²+11²

81+100+121

302