Question

THE SUM OF 3 CONSECUTIVE INTEGERS IS 45. WHAT ARE THESE INTEGERS?

Answer 1

Let the first no. be x
second be (x+1),third be(x+2).
Acc. to ques....
x+(x+1)+(x+2)=45
=> 3x+3=45
=> 3x=42
=> x=14

Therefore,
First no. - 14
Second no.- x+1=14+1+=15
Third no. - x+2=14+2=16

Answer 2

Answer:

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 45

3X + 3 = 45

3X + 3 - 3 = 45 - 3

3X = 42

3X/3 = 42/3

X = 14

Which means that the first number is 14, the second number is 14 + 1 and the third number is 14 + 2. Therefore, three consecutive integers that add up to 45 are 14, 15, and 16.

14 + 15 + 16 = 45

We know our answer is correct because 14 + 15 + 16 equals 45 as displayed above.