Question

the sum of 3 consecutive multiples of 11 is 330 find the multiples

Answer 1

3 consecutive no. are = x
x+1
x+2
11(x+x+1+x+2)=330
3x+3=30
3x=27
x=9
no. are 9,10,11

Answer 2

let us take terms x, x+11, x+22

x+ x+11+x+22=330

3x+33=330

3x=330-33

x=297/3=99

x+11=99+11
=110
x+22=99+22
=121