The sum of 3 consecutive multiples of 11 is 363. Find these multiples.
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Answer:
110+121+132=363
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let first no be x
then second term becomes x+11
thid term becomes x+22
x+x+11+x+22=363
=3x+33=363
=3x=363-33
=3x=330
=x=330/3
x=110
x+11=121
x+22=132
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