Question

the sum of 3 consecutive multiples of 11 is 363 find these multiples

Answer 1

Let the first digit be 11x
Next be 11x+11 and 11x+22
So 11x+11x+11+11x+22=363
33x+33=363
33x=330
X=330/33
X=10
So numbers are=11*10=110
11*10+11=121
11*10+22=132

Answer 2

Hi ,

Let x , ( x + 11 ) , ( x + 22 ) are three

consecutive multiples of 11

Sum of these numbers = 363

x + ( x + 11 ) + ( x + 22 ) = 363

3x + 33 = 363

3x = 363 - 33

3x = 330


x = 330/3

x = 110

Therefore ,

Required numbers are ,

110 , ( 110 + 11 ) , ( 110 + 22 )

110 , 121 , 132

I hope this helps you.

: )