Question

the sum of 3 consecutive multiples of 11 is 363 find these multiples

Answer 1

Hi Friend !!!

Here is ur answer !!!

Let the multiples be 11x, 11x+11 , 11x+22

11x+11x+11+11x+22 = 363

33x+33 = 363

33(x+1) = 363


x+1 = 363/33

x+1 = 11

x = 10


So the numbers are

11x = 110


11x+11 = 110+11 = 121

11x+22 = 121+11= 132


Hope it helps u : )

Answer 2

Hey mate,
Let the first multiple be x
So second multiple will be x + 11
And third multiple will be x + 22
Their sum is 363
A/q ,
x+x+11+x+22=363
3x+33= 363
So, 3x= 363-33
So, 3x = 330
and x = 330/3
Therefore x = 110
Second multiple is 110+11=121
Third multiple is 110+22=132
This the answer hope it will help you.