Question

the sum of 3 consecutive multiples of 8 is 888. Find the multiples.

Answer 1

Heya!!!

suppose three multiples are x-1,x,x+1 th multiples of 8.

Their sum is 888. So, 8(x-1)+8x+8(x+1)=888

24x=888

3x=111.

x=111/3=37.
Multiples are:

8(x-1)=8*36=288
8*37=296

8*38=304.

Hope this helps you ☺☺

Answer 2

according to question

(x+(x+1)+(x+2))×8 = 888
3x + 3= 111
3x = 108
X = 36

hence

the no. is = 36,37 and 38

then multiples are
36×8=288
37×8=296
38×8=304

I hope it will help you..