The sum of 3 consecutive number of the 4 numbers a,b,c,d are 4613,4961,5010,5099 then what is the largest number among a,b,c,d?
Answers
Answer:
The largest number among a, b, c and d is d i.e 1948.
Step-by-step explanation:
Given the sum of 3 consecutive number of the 4 numbers a,b,c,d are 4613,4961,5010,5099. we have to find the largest number among a,b,c,d
Given the sum of 3 consecutive number
Hence, the sets of consecutive numbers are
a,b,c
a,c,d
a,b,d
b,c,d
According to question,
a+b+c=4613 → (1)
a+c+d=4961 → (2)
a+b+d=5010 → (3)
b+c+d=5099 → (4)
Solving equation (1), (2), (3) and (4), we get
a = 1462, b= 1600 , c= 1551, d= 1948
Hence, the largest number among a, b, c and d is d i.e 1948.
"Answer: d = 1948
Given:
4 numbers are given as a, b, c and d.
Sum of 3 consecutive numbers are 4613, 4961, 5010 and 5099.
Solution:
Concept: “sum of three consecutive numbers will exclude one number that can be found by subtracting it from total sum”.
The numbers given a, b, c and d can be formed as:
a + b + c = 4613 -------------- (1)
a + c + d = 4961 --------------(2)
a + b + d = 5010 --------------(3)
b + c + d = 5099 --------------(4)
Adding all the four formations will give us: (1) + (2) + (3) + (4)
3a + 3b + 3c + 3d = 19683
3 (a + b + c + d) = 19683
Thus,
a + b + c + d = 6561 -------------(5)
On substituting equation (1) in (5) will give us d:
4613 + d = 6561
d = 1948;
similarly substituting (2) (3) and (4) in (5) will give us the values of b, c and a respectively:
b= 1600; c= 1551; a = 1462
Comparing all the values of a, b, c and d, it is inferred that d is the largest number: d = 1948.
"