Question

The Sum Of 3 consecutive numbers is 39.Find the numbers​

Answer 1

Answer:

Let the numbers b x,x+1,x+2

ATP x+x+1+x+2 = 39

3x+3=39

3x= 39-3

3x=36

x= 36/3

x= 12

Therefore the numbers are

12,13,14

Step-by-step explanation:

Answer 2

Answer:

$\huge\mathfrak{\red{\underline{\pink{\boxed{Answer \: :-}}}}}$

➜let the three consecutive numbers be:-

• first no.(x)
• second no.(x+1)
• third no.(x+2)

➜sum of all three consecutive numbers = 39

$\huge{\sf{\underline{\red{Equation formed :-}}}}$

$\small{\sf{\underline{\orange{\boxed{x\:+\:x\:+\:1\:+\:x\:+\:2\:=\:39}}}}}$

$\huge{\sf{\underline{\pink{Solution :-}}}}$

• x + x + 1 + x + 2 = 39

• 3x + 3 = 39(after adding like terms)

• 3x = 39 - 3 = 36(after transporting 3)

• x = 36 / 3 (after transporting 3)

• x = 12

$\small{\sf{\underline{\pink{first no = x = 12 ,</p><p> second no = x + 1 = 12 + 1 = 13 ,</p><p> third no = x + 2 = 12 + 2 = 14 ,}}}}$

➜ There fore, three consecutive numbers are:

• 12
• 13
• 14

Thank you :)