the sum of 3 consecutive odd naturals numbers is 69 .find the prime number.
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1st no = 21
2nd no = 23
3rd no = 25
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2nd no = 23
3rd no = 25
Hope it helps you and if it does please mark my answer as the brainliest
if you wish you can become my follower so that I can help you with your doubts
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Bhuroh:
very thanks for the answer
Answered by
1
Hey
Here is your answer,
Let the three consecutive odd natural numbers be x , x+2 , x+4
X + x + 2 + x + 4 = 69
3x + 6 = 69
3x = 69 - 6
3x = 63
X = 63/3
X = 21
X+2 = 21+2 = 23
X+4 = 21+4 = 25
Therefore the numbers are 21 , 23 and 25.
Among the three numbers , 23 is the number .
Hope it helps you!
Here is your answer,
Let the three consecutive odd natural numbers be x , x+2 , x+4
X + x + 2 + x + 4 = 69
3x + 6 = 69
3x = 69 - 6
3x = 63
X = 63/3
X = 21
X+2 = 21+2 = 23
X+4 = 21+4 = 25
Therefore the numbers are 21 , 23 and 25.
Among the three numbers , 23 is the number .
Hope it helps you!
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