Question

the sum of 3 consecutive term in an AP is 108 and the product of the two smaller term is 1116. find them ​

Answer 1

Step-by-step explanation:

x,x+1 and x+2

Now ,according to question,

x+(x+1)+(x+2)=108

3x+3=108

3x=105

x=35

Required three numbers are,

x=35,x+1=36 and x+2=37

Hence, this is the answer.

Answer 2

Answer 31,36,41

Step-by-step explanation: let three consecutive numbers of Ap be           a-d,a,a+d

a-d+a+a+d=108;

3a=108;

a=36

a(a-d)=1116

36(36-d)=1116

1296-36d=1116

1296-1116=36d

180=36d

d=5

the terms are a-d=36-5=31;

                        a=36;

                        a+d=36+5=41;

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