Question

the sum of 3 consecutive terms in an AP is 6 and their product is -120. find 3 numbers.​

Answer 1

Answer:

-6, 2, 10 or 10, 2, -6

Step-by-step explanation:

Let the numbers be b-d, b, b+d

So sum = 3b=6

So b= 2

Now, (b-d)(b)(b+d) = -120

(2-d)(2+d)2 = -120

4 - d^2 = -60

d^2 = 64

d = 8 or -8

So numbers are b-d, b, b+d = -6,2,10 or 10,2,-6

Hope it helps

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