Question

The sum of 3 consecutive terms of an AP is 3 and their product is -35 find the numbers

Answer 1

Answer:

Let 3 consecutive no. be (a-d) (a) (a+d)

a-d+a+a+d=3

3a=3

a=1

(a-d)(a+d)a= -35

a²-d²(a)= -35

1-d²= -35

d²=36

d=6

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Answer 2

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