The sum of 3 numbers in a AP is 12 and sum of
their cubes is 288. find the numbers
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Thus, we have a−d+a+a+d=12. We have to now find the value of common difference d. We know that the sum of cubes of the numbers is 288. Thus, we have (a−d)3+a3+(a+d)3=288.
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Answer:
3,4,5 are the A.P
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