Question

The sum of 3 numbers in A.P. is 3 and their product is -35 . find the numbers.

Answer 1

Let the numbers be ( a - d), a and (a+d)

Sum = 3

=> a - d + a + a + d = 3

=> 3a = 3

=> a = 1

Now,

Product = - 35

=> (a-d) (a) (a+d) = - 35

=> (a^2 - d^2) (1) = - 35

=> ( 1 - d^2) = - 35

=> d^2 = 36

=> d = 6

Required numbers are - 5, 1 and 7