The sum of 3 numbers in A.P. is 3 and their product is -35 . find the numbers.
Answers
Answered by
3
Let the numbers be ( a - d), a and (a+d)
Sum = 3
=> a - d + a + a + d = 3
=> 3a = 3
=> a = 1
Now,
Product = - 35
=> (a-d) (a) (a+d) = - 35
=> (a^2 - d^2) (1) = - 35
=> ( 1 - d^2) = - 35
=> d^2 = 36
=> d = 6
Required numbers are - 5, 1 and 7
Sum = 3
=> a - d + a + a + d = 3
=> 3a = 3
=> a = 1
Now,
Product = - 35
=> (a-d) (a) (a+d) = - 35
=> (a^2 - d^2) (1) = - 35
=> ( 1 - d^2) = - 35
=> d^2 = 36
=> d = 6
Required numbers are - 5, 1 and 7
Similar questions