The sum of 3 numbers in AP is 12 and sum of the cubes is 288 find the number.
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let 3 numbers be a+d , a , a-d
according to 1st condition
a+d+a+a-d=12
3a=12
a=4
according to 2nd condition
(a+d)³+(a)³+(a-d)³=288
according to 1st condition
a+d+a+a-d=12
3a=12
a=4
according to 2nd condition
(a+d)³+(a)³+(a-d)³=288
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