Question

the sum of 3 positive numbers in AP is 189. The sum of their squares is 11915. Find their products.

Answer 1

hope this may help you

Answer 2

Answer: let the numbers be : a-d, a,a+d

according to question,

a-d + a + a+ d= 189

3a = 189

a = 63

now,

a^2 + (a-d)^2 + (a+d)^2 = 11915

3a^2 + 2d^2 = 11915

3(63)^2 + 2d^2 = 11915

2d^2 = 11915- 11907

2d^2 = 8

d^2 = 4

d = 2

therefore, ap = 61,63,65

product of 61,63,65 = 249795

hope it helps :) :)