Question

the sum of 3rd and 10th term of an AP is equal to sum of 5th and 2nd term if 7th term is 27 then find AP​

Answer 1

Answer:

Step-by-step explanation:

given

t7 = 27

a + 6d = 27          [ tn = a + ( n - 1 ) d ]

a = 27 - 6d ----- 1

t3 + t10 = t5 + t2

a + 2d + a + 9d = a + 4d + a + d          [ tn = a + ( n - 1 ) d ]

2a + 11d = 2a + 5d

2a + 11d - 2a - 5d = 0

6d = 0  

d = 0

sub d = 0 in 1

a = 27 - 0

a = 27

∴ the AP is

a, a +d, a + 2d, ....      [ a = 27, d = 0]

27, 27, 27,.....

i think this is the answer...

hope it helps

Answer 2

Answer:

Step-by-step explanation:

given

t7 = 27

a + 6d = 27          [ tn = a + ( n - 1 ) d ]

a = 27 - 6d ----- 1

t3 + t10 = t5 + t2

a + 2d + a + 9d = a + 4d + a + d          [ tn = a + ( n - 1 ) d ]

2a + 11d = 2a + 5d

2a + 11d - 2a - 5d = 0

6d = 0  

d = 0

sub d = 0 in 1

a = 27 - 0

a = 27

∴ the AP is

a, a +d, a + 2d, ....      [ a = 27, d = 0]

27, 27, 27,.....