the sum of 3rd and 10th term of an AP is equal to sum of 5th and 2nd term if 7th term is 27 then find AP
Answers
Answered by
1
Answer:
Step-by-step explanation:
given
t7 = 27
a + 6d = 27 [ tn = a + ( n - 1 ) d ]
a = 27 - 6d ----- 1
t3 + t10 = t5 + t2
a + 2d + a + 9d = a + 4d + a + d [ tn = a + ( n - 1 ) d ]
2a + 11d = 2a + 5d
2a + 11d - 2a - 5d = 0
6d = 0
d = 0
sub d = 0 in 1
a = 27 - 0
a = 27
∴ the AP is
a, a +d, a + 2d, .... [ a = 27, d = 0]
27, 27, 27,.....
i think this is the answer...
hope it helps
Answered by
0
Answer:
Step-by-step explanation:
given
t7 = 27
a + 6d = 27 [ tn = a + ( n - 1 ) d ]
a = 27 - 6d ----- 1
t3 + t10 = t5 + t2
a + 2d + a + 9d = a + 4d + a + d [ tn = a + ( n - 1 ) d ]
2a + 11d = 2a + 5d
2a + 11d - 2a - 5d = 0
6d = 0
d = 0
sub d = 0 in 1
a = 27 - 0
a = 27
∴ the AP is
a, a +d, a + 2d, .... [ a = 27, d = 0]
27, 27, 27,.....
Similar questions