the sum of 3rd and 7th term of an a.p is 6 and the product is the sum of first 20 terms. in an ap
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The sum of the third and the seventh terms of an AP is 6 and their product is 8. ... + (n − 1)d
Hence, 3rd term of AP = a3 = a + 2d
and 7th term of AP = a7 = a ... 6 a + 4d = 6/2 a + 4d = 3
Product of the third and seventh terms is 8 a3 ... if a = 5 and d = (−)/,
the sum of first sixteen terms of the AP is 20.
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