the sum of 4 consecutive multiples of 11 is 506 find these multiples
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HEYA ..
LET THE NO. BE X
THERE ARE 4 COSECUTIVE MULTIPLES..
== THEREFORE THE NUMBER WILL BE
=X, 11+X, 22+X, 33+X
= GIVEN THEIR SUM= 506
= X+11+X+22+X+33+X = 506
= 4X + 66= 506
= 4X = 506 - 66
= 4X = 440
THEREFORE X = 440/ 4
= 11O = X
THEREFORE THE MULTIPLES ARE
110, 110+11, 110+22, 110+33
=110 ,121, 132,143...
HOPE HELPED...
AND ALSO MRK BRAINLIEST IF HELPED... ,
LET THE NO. BE X
THERE ARE 4 COSECUTIVE MULTIPLES..
== THEREFORE THE NUMBER WILL BE
=X, 11+X, 22+X, 33+X
= GIVEN THEIR SUM= 506
= X+11+X+22+X+33+X = 506
= 4X + 66= 506
= 4X = 506 - 66
= 4X = 440
THEREFORE X = 440/ 4
= 11O = X
THEREFORE THE MULTIPLES ARE
110, 110+11, 110+22, 110+33
=110 ,121, 132,143...
HOPE HELPED...
AND ALSO MRK BRAINLIEST IF HELPED... ,
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