the sum of 4 consecutive numbers 354 what is the second number
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let the 4 consecutive numbers be x, x+1, x+2 and x+3.
sum=354
x+(x+1)+(x+2)+(x+3)=354
x+x+1+x+2+x+3=354
3x+6=354
3x=354-6
3x=348
x=348/3
x=116.
second number,
x+1=116+1
=117.
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sindukar:
there is a mistake in the middle. it is 4x, and not 3x. so the second number will be 87+1=88
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1st no. x
2nd no. x+1
3rd no.x+2
4th no. x+3
A/q= x+x+1+x+2+x+3=354
= 4x+6=354
=4x=354-6
= 4x= 348
= x=348/4
=x= 87
Now, only 2nd no. is x+1= 87+1= 88 ans.
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2nd no. x+1
3rd no.x+2
4th no. x+3
A/q= x+x+1+x+2+x+3=354
= 4x+6=354
=4x=354-6
= 4x= 348
= x=348/4
=x= 87
Now, only 2nd no. is x+1= 87+1= 88 ans.
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