Question

The sum of 4 consecutive terms in an ap is 24 and their product is 4.5. Find these terms

Answer 1

Let the four consecutive terms be (a-3d),(a-d),(a+d),(a+3d)

=》(a-3d)+(a-d)+(a+d)+(a+3d)=4

${a}^{4} = 4 \\ a = 2 \sqrt{4}$

=》(a-3d)(a-d)(a+d)(a+3d)=4.5

then find d by putting values of a....

finally put the value of d and a and find the terms...