The sum of 4^th & 8^th term of an Ap is 24 and sum of 6^th and 10^th term is 44 find Ap
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Here,
a
4
=a+3d
a
8
=a+7d
Therefore,
a+3d+a+7d=24
2a+10d=24
a+5d=12 …… (1)
Again,
a
6
=a+5d
a
10
=a+9d
Therefore,
a+5d+a+9d=44
2a+14d=44
a+7d=22 ……. (2)
Solving equations (1) and (2), we get
d=5 and a=−13
Therefore,
a
1
=a=−13
a
2
=a+d=−13+5=−8
a
3
=a+2d=−13+10=−3
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