Question

the sum of 4 times of a number and half of it is one whole two by 3. let us find the number. (plz don't spam if don't know the answer ignore)​

Answer 1

Answer:

hence,the required no is 144

Step-by-step explanation:

Solution

Correct op

tion is B)

Let the number be x. 

Then, (2x+3x+4x)−x=12,  

L.C.M of 2,3,4=12, 

Thus multiplying above equation with 12 both sides,

⇒12×2x+12×3x+12×4x−12×x−12×12

⇒6x+4x+3x−12x=144

⇒13x−12x=144⇒x=144.

Hence, the required number is 144.

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Answer 2

Answer:

∴ The required value of $x$ is $0.37$.

Step-by-step explanation:

In context with question asked,

• We have to find the number.
• The given condition is, "the sum of $4$ times of a number and half of it is one whole two by $3$."
• Let, $x$ be the number.
• According to given condition, the required equation is,

          $4x+\frac{x}{2} =1\frac{2}{3}$

• Converting mixed fraction into improper fraction, we get

         ∴  $4x+\frac{x}{2} =\frac{5}{3}$

• By cross multiplication, we get

           ∴ $\frac{8x+x}{2} =\frac{5}{3}$

• By Cross multiplication, we get

           ∴ $3\times 9x=2\times 5$

               ∴ $27x=10$

               ∴ $x=\frac{10}{27}$

         

• ∴ The required value of $x$ is $\frac{10}{27}$.