The sum of 4a-7c+5b,3a+13c and -9b+5c is
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(4a-7c+5b)+(3a+13c)+(-9b+5c)
=4a-7c+5b+3a+13c-9b+5c
=4a+3a-7c+5c+13c+5b-9b
=7a-5c+13c-4b
=7a+9c-4b
Therefore,Answer is......
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