Question

the sum of 4th and 6th terms of an AP is 0 and the product of 6th and 9th term is 36 prove 5 is 0 ​

Answer 1

Step-by-step explanation:

a+3d+a+5d=0

2a+8d=0   a+4d=0     a= -4d---->1

(a+5d) (a+8d)= 36   (sub 1)

(-4d+5d) (-4d+8d) = 36

(d) (4d) = 36

4d^2=36

d^2=9

d=3

a=-4x3

a=-12

5th term

=> a+4d= -12+4(3)

              = -12+12

              =0

hence proved