The sum of 4th and 8th term
of on AP is 24 and 6th and
and 2th term is 44 find the
Sum of first 10 term
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Step-by-step explanation:
For the sum of 4th and 8th term
a+(4-1)d + a+(8-1)d=24
a+3d+a+7d=24
2a+10d=24
a+5d=12......... 1
Again, a/q
a+(6-1)d + a+(2-1)d=44
a+5d+a+d=44
2a+6d=44
a+3d=22..........2
Now subtracting eq2 from eq1
a+5d-a-3d=12-22
2d=-10
d=-5
So, a=-37
Now u can find first 10 terms
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