Question

The sum of 5 consecutive integers is 110 what is the fourth number

Answer 1

Hi, my friend.
Here is your answer.

Let five consecutive numbers are
x ,(x+1) ,(x+2) ,(x+3), (x+4)
Sum is
x+x+1+x+2+x+3+x+4 =110
5x + 10 =110
5x = 110-10
5x= 100
x= 100/5
x =20

Now, Fourth number =x+3
=20+3
=23
Hope it will help you my friend...........

Answer 2

Answer:

Required fourth integer is 23.

Step-by-step explanation:

Given,sum of 5 consecutive integers is 110.

Here we want to find fourth integer.

But now question is what is Integer ?

A whole number that can be positive, negative, or zero is called integer.

For example, 1,2,-1,0,5 all are integers

Let,5 consecutive integers be

$x,(x + 1),(x + 2),(x + 3),(x + 4)$

According to question sum of

$x,(x + 1),(x + 2),(x + 3),(x + 4)$

is equal to 110.

So,

$x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 110$

We are removing brackets,

$x + x + 1 + x + 2 + x + 3 + x + 4 = 110$

We are separating variable and constant part,

$x + x + x + x + x = 110 - 1 - 2 - 3 - 4 \\ 5x = 110 - 10 \\ 5x = 100 \\ x = \frac{100}{5} \\ x = 20$

So, consecutive 5 integers are

$20,(20 + 1),(20 + 2),(20 + 3),(20 + 4) = 20,21,22,23,24$

Therefore required fourth integer is 23.

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