Question

The sum of 5 consecutive integers is 130 whats the largest interger of the five

Answer 1

Let the five consecutive numbers be x, x+1,x+2, x+3, x+4.
By adding them up, we will get the following equation :
x+(x+1)+(x+2)+(x+3)+(x+4)=130
=> 5x +10 = 130
=>5x = 130-10
=>5x = 120
=>x = (120÷5)= 24
Hence, the largest integer of the five is (x+4), which is (24+4)=28.

I hope you get your question answered sufficiently. Happy learning.

Answer 2

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