The sum of 5 consecutive integers is 130 whats the largest interger of the five
Answers
Answered by
7
Let the five consecutive numbers be x, x+1,x+2, x+3, x+4.
By adding them up, we will get the following equation :
x+(x+1)+(x+2)+(x+3)+(x+4)=130
=> 5x +10 = 130
=>5x = 130-10
=>5x = 120
=>x = (120÷5)= 24
Hence, the largest integer of the five is (x+4), which is (24+4)=28.
I hope you get your question answered sufficiently. Happy learning.
By adding them up, we will get the following equation :
x+(x+1)+(x+2)+(x+3)+(x+4)=130
=> 5x +10 = 130
=>5x = 130-10
=>5x = 120
=>x = (120÷5)= 24
Hence, the largest integer of the five is (x+4), which is (24+4)=28.
I hope you get your question answered sufficiently. Happy learning.
Answered by
2
hope thus helps uhh...marrk as brainliest nd follow me☺☺
Attachments:
Similar questions