The sum of 5 consecutive integers is 505
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let 5 consecutive integers are
x, x+1, x+2, x+3, x+4,
The sum of 5 consecutive integers = 505
x + x+1 + x+2 + x+3 + x+4 = 505
5 x + 10 = 505
5 x = 505 - 10
5 x = 495
x = 495 / 5
x = 99
so, the answer : 99 , 100, 101, 102, 103
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x, x+1, x+2, x+3 and x+4 are the consecutive integers,,,
x+x+1+x+2+x+3+x+4 = 505
5x+10 = 505
5x = 505-10
5x = 495
x = 495/5
x = 99
Hence, the consecutive integers are 99, 100, 101, 102 and 103.
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