Math, asked by isaiah2005silva, 1 year ago

The sum of 5 consecutive integers is 505

Answers

Answered by oshoraa
0

let 5 consecutive integers are

x,  x+1,  x+2,  x+3,  x+4,  

The sum of 5 consecutive integers = 505

x + x+1 + x+2 + x+3 + x+4  =  505

         5 x   +   10                =  505

                       5 x             =  505 - 10

                       5 x             =  495

                          x              =  495 / 5  

                          x              =   99

so, the answer :   99 ,  100,  101,  102,  103

Answered by aditi13112003
0

x, x+1, x+2, x+3 and x+4 are the consecutive integers,,,

x+x+1+x+2+x+3+x+4 = 505

5x+10 = 505

5x = 505-10

5x = 495

x = 495/5


x = 99

Hence, the consecutive integers are 99, 100, 101, 102 and 103.

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