Question

the sum of 5 consecutive numbers is 200 whats the smallest number

Answer 1

Step-by-step explanation:

let the numbers be a ,a+1,a+2,a+3,a+4

Sum of 5 consecutive numbers=n/2(2(first number+last number)

200=5/2(a+a+4)

200=5/2×2a+4

200×2/5=2a+4

80=2a+4

76=2a

a=38

Hence the smallest number is 38

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