the sum of 5th and 9th of an A.P. is 72 and the sum of 7th and 12th term is 97 find A.P.
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12
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the sum of 5th , 9th term of an ap is 72 and the sum of 7th and 12th term is 97 find the ap. let a is first term and difference is d
5th term= a+4d, 9th term= a +8d
so, sum = a+4d + a +8d = 2a +12 d = 72
2a +12 d = 72-----(1)
7th= a +6d and 12th = a+11 d
so sum = a +6d + a +11d = 2a +17 d = 97
=>2a +12 d + 5d = 97
=>72 + 5d = 97 (putting value of 2a + 12d from eq 1)
=>5d= 97-72= 25
=>d= 5
put value of d in eq 1
=> 2a +12 d = 72
=> 2a + 12 X 5 =72
=>2a = 72 - 60 =12
=> a =6 and d=5 answer
Answered by
2
Answer:
1st
a+4d+a+8d=72
=2a+12d=72
=a+6d=36
2nd
a+6d+a+11d=97
=2a+17d=97
1st 2a+12d=72
2nd 2a+17d=97
- - -
-5d= 25
d=5
1st a+30=36
a=6
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