The sum of 6 consecutive even number.
what is the fourth number in the sequence
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Answer:
6 consecutive even numbers
First x
Second x+2
Third x+4
Fourth x+6
Fifth x+8
Sixth x+10
126=x+x+2+x+4+x+6+x+8+x+10
126=6x+30
Subtract 30 from both sides
96=6x
Divide both sides by 6
x=16
Fourth x+6=16+6=22
Step-by-step explanation:
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Answered by
2
Answer:
Fouth number in the sequence is 22.
Step-by-step explanation:
let ,
1st consecutive number be x.
2nd be x+2
3rd be x+4
4th be x+6
5th be x+8
6th be x+10
so,by given condition,
(x) +(x+2)+(x+4)+(x+6)+(x+8)+(x+10)=126
= x+x+2+x+4+x+6+x+8+x+10=126
= 6x+30=126
= 6x = 126 -30
= 6x = 96
= x = 96/6
= x = 16
hence,
fourth number
= x +6
=16+6
= 22
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