the sum of a 2 digit no. and the no. obtained by reversing its digits is 121 . find the no. if its units place is 5
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Answer:
65
Step-by-step explanation:
Let our number is xy.
so always remember two digit number is written as xy = 10x+y
and it's reverse yx= 10y+x
Now sum = 121
so
10x+y+10y+x= 121
11x+11y = 121
11(x+y)= 121
x+y = 121/11
x+y = 11
Now unit digit which is y is given as 5
Hence,
x + 5 = 11
x = 11-5
x = 6
Hence we get our number as xy = 65
Thank you.
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