The sum of a 2-digit number is 7. If the digits are reversed, the number formed is 9 less than the original number. Find the number.
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Answer:
Take the no xy. this means 10x+y( expansion form).
reverse the digits then the no is yx
yx= 10y+ x
the difference = 9x-9y
in the question the difference is given
9(x-y) = 9
so x-y =1,
sum of the digits is x+y = 7
from the 2 statement s x=4, y=3
finally the no is 43
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