Question

The sum of A and B's age is 43 years. 11 year hence, A's age will be 7/6 times B's age then. Find B's present age.

Answer 1

Hii ☺ !!


Let present age of A and B be X and Y years.



A/c,



x + y = 43 --------(1)


And,



x + 11 = 7/6 ( y + 11 )


x + 11 = 7 ( y + 11 ) / 6



6 ( x + 11 ) = 7y + 77



6x + 66 = 7y + 77



6x - 7y = 77 - 66


6x - 7y = 11 -------(2)


from equation (1) , we get

x + y = 43


x = ( 43 - y ) ------(3)

Putting the value of x in equation (2) , we get


6x - 7y = 11

6 ( 43 - y ) - 7y = 11



258 - 6y - 7y = 11



-13y = 11 - 258



-13y = -247



y = 19


Putting the value of y in equation (3) ,we get



x = 43 - y = 43 - 19


x = 24 years.


Hence,


Present age of A = x = 24 years.

And,

Present age of B = y = 19 years.

Answer 2

solution :

according to the questions

Let Present ages of A and B be x and y years.

also ,

mentioned in question sum of A and B is equal to 43.

According to the question ,

here a equal to x and b equal to y.

x + y = 43 -

Equation (1)

now,

After 11 years age of A = ( x + 11 ) .

And,

After 11 years age of B = ( y + 11 ).

According to the question,

x + 11 = 7/6 of y + 11

x + 11 = 7y + 77 / 6

6 ( x + 11 ) = 7y + 77

6x + 66 = 7y + 77

6x - 7y = 11 - Equation (2)

From equation (1) , we get

x + y = 43

x = ( 43 - y ) - Equation (3).

Putting the value of x in equation (2) , we get

6x - 7y = 11

6 ( 43 - y ) - 7y = 11

258 - 6y - 7y = 11

-13y = -247

y = 19

Substitute the value of y in (3) , we get

x = 43 - y = 43 - 19

x = 24 years.

Hence,

Present age of A equal to x equal to 24 years.

also ,

Present age of B equal to y equal to 19 years.

✓ Hope it helps ♥

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