Question

the sum of a digits of a 2 digit number is 11. the number obtained by interchanging the digits exceeds the original number by 27.find the number

Answer 1

let unit digit no be x and tens digit no be y.Then the no is 10y+x
now x+y=11..........(1)
(10y+×) _ (10×+y)=27..........(2)
solving 1&2 get x&y. put the value of x&y in 10x+y and get the result